Hi folks!

Team SSCHacks has compiled a list of the most efficient Calculation SuperHacks for every candidate of SSC CGL 2018. Let’s see them one by one.

1. Squaring a number instantly 

Well, you might have come across various tricks to find the square of a number, but I can bet you that this trick is the simplest and the fastest. Initially memorize squares of numbers up to 25. I think many of you might be knowing it already, but for those who don’t, please mug it. Now, this trick will help you in squaring numbers up to 125 and for SSC you need this much only.

(a) For numbers close to 50

                   (i) Numbers less than 50

                             (ii) Numbers greater than 50
The process is almost same. 

Compute (N- 50)                                                                                                                                                             Add this difference to 25
E.g. 56*56=
            1. 56-50 = 6
            2. Last two digits = 6 * 6 = 36 
            3. First two digits = 25 + 6 = 31
Therefore, 56 * 56 = 3136

(b) Numbers close to 100
                     

                               (i) Numbers less than 100

                                (ii) Numbers greater than 100
The process is almost same                                                                                                                   Compute (N-100)
                  Add this difference to N
E.g. 107*107=
                   1. 107-100= 7
                   2. Last two digits = 7 * 7 = 49
                   3. First three digits = 107 + 7 = 114
Therefore, 107 * 107 = 1144 

 

2. Squaring a number containing only ‘1’.

E.g. 111, 1111, 1111111, etc. Just count the number of ones.
Like in 1111, there are 4 ones.                                                                                                                         So the square of 1111 is 1234321 (go from 1 to 4 and then back).                                       Similarly, the square of 111111 = 12345654321

3. Finding the product of two numbers of the form ab and ac, such that b+c=10.

E.g. product of 43 and 47                                                                                                                               Last two digits = 3*7 = 21
First two digits = 4*(4+1) = 20
Hence 43*47 = 2021

4. Finding product of two numbers close to 100.

(a) 103*109
Last two digits = 3*9 = 27
First three digits = (103 + 9) or (109 + 3) = 112
So 103*109 = 11227

(b) 92*97
Last two digits = 8*3 = 24 [100-92= 8 and 100-97= 3]
First two digits = (92-3) or (97-8) = 89
Hence 92*97 = 8924

Bonus Hack :
A very common question in SSC CGL, 

Post 8- 1

Note: Always take the difference between the numerator and the
denominator as positive.
Answer : 3*/(4 – 3)* 20 = 60 minutes

Post 8- 2

Example:                                                                                                                                                   Rakesh runs at 5/4 of his usual speed and reaches the playground 5 minutes earlier. What is his usual time?
Answer : 5/(5 – 4)* 5 = 25 minutes

Were these helpful or did we miss any of the important hacks?

Tell us whatever you feel and we’ll be more than happy to respond.

Happy Learning.
All the Best!

– Team  SSCHacks

Kickstart the SSC CGL 2018 preparation with these AMAZING SUPERHACKS !!

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